SBI PO 02 July 2016 Shift 1 Paper

I. 14x2 – 37x + 24 = 0
⇒ 14x2 – 21x – 16x + 24 = 0
⇒ 7x (2x – 3) – 8 (2x – 3) = 0
⇒ (7x – 8) (2x – 3) = 0
⇒ x =

8

7

or

3

2

II. 28y2 – 53y + 24 = 0
⇒ 28y2 – 21y – 32y + 24 = 0
⇒ 7y (4y – 3) – 8 (4y – 3) = 0
⇒ (7y – 8) (4y – 3) = 0
⇒ y =

8

7

or

3

4

Clearly, x ≥ y