SAT Mathematics Practice Test 7

The slope of the line can be found by selecting any two points $\left({\mathit{x}}_1,{\mathit{y}}_1\right)$ and $\left({\mathit{x}}_2,{\mathit{y}}_2\right)$ on the line and then dividing the difference of the y-coordinates $\left({\mathit{y}}_2-{\mathit{y}}_1\right)$ by the difference of the x-coordinates $\left({\mathit{x}}_2-{\mathit{x}}_1\right)$. Using the points $\left(-6,-\frac{27}{5}\right)$ and $\left(9,\frac{3}{5}\right)$, the slope is $\frac{\frac{3}{5}-\left(-\frac{27}{5}\right)}{9-\left(-6\right)}=\frac{\frac{30}{5}}{15}$. This can be rewritten as $\frac{6}{15}$, which reduces to $\frac{2}{5}$. Any of the following equivalent expressions can be gridded as t hecorrect answer: 2/5, .4, .40, .400, 4/10, 8/20.