SAT Mathematics Practice Test 4

© examsiri.com

Question : 19 of 58

Marks: +1, -0

-3x+4y=20

6x+3y=15

If

(x,y)

is the solution to the system of equations above, what is the value of ?

Your Answer:

Solution:

Multiplying each side of

−3x+4y=20

by 2 gives

−6x+8y=40.

Adding each side of

−6x+8y=40

to the corresponding side of

6x+3y=15

gives

11y=55

,or

y=5.

Finally, substituting

5

for

y

in

6x+3y=15

gives

6x+3(5)=15,

or x=0.

© examsiri.com

Go to Question:

Prev Question

Next Question