SAT Mathematics Practice Test 3

Question : 9 of 58

Marks: +1, -0

$kx-3y=4$
$4x-5y=7$
In the system of equations above,

k

is a constantand

x

and

y

are variables. For what value of k will the system of equations have no solution?

Solution:

[kx - 3y = 4]× 5/3

4x - 5y = 7

set the coefficients equal to a different constant

{-3y}/1× 5/3 = -5y

{[5/3 k x = 4 x]}/5/3

k = 4/{5/3} = 4/1 × 3/5 = 12/5

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