SAT Mathematics Practice Test 2

Since the square of any real number is non-negative, every point on the graph of the quadratic equation $\mathit{y}=\left(\mathit{x}-2\right)2$ in the xy-plane has a non-negative y-coordinate. Thus, $\mathit{y}\ge 0$ for every point on the graph. Therefore, the equation $\mathit{y}=\left(\mathit{x}-2\right)2$ has a graph for which y is always greater than or equal to $-1$.
Choices A, B, and D are incorrect because the graph of each of these equations in the xy-plane has a y-intercept at $\left(0,-2\right)$. Therefore, each of these equations contains at least one point where y is less than $-1$.