Sainik School Entrance Exam 2020 Solved Paper

From the question, $\mathrm{overline}148101\mathit{a}095$ is multiple of 11,
where $\mathit{a}$ is a digit
A number is divisible by 11 if the difference between the sum of its digit at odd places and the sum of its digits at even places is either 0 or $\mathit{a}$ number divisible by 11
∴ (Sum of digit at odd place)$-$(Sum of digit at even place)
$=\left(5+0+1+1+4\right)-\left(9+\mathit{a}+0+8+1\right)$
$=11-\left(18+\mathit{a}\right)=11-18-\mathit{a}=-7-\mathit{a}$
$=-\left(7+\mathit{a}\right)$
Where, $\mathit{a}=4$
Then $-\left(7+\mathit{a}\right)$ is divisible by 11
So, the value of $\mathit{a}$ is 4 .