Sainik School Entrance Exam 2020 Solved Paper

Question : 33 of 150

Marks: +1, -0

Mohan invested a sum of

₹ 12,500

12 \%

per annum compound interest. He received an amount of

₹ 15,680

after

x

year. Then the value of

x

Solution:

(d) From the question,

{\P}=₹ 12,500, r=12 \%

{\A}={\₹} 15,680, n=x

years

∴ {A}={\P}(1+{r}/{100})^n

⇒ ₹15,680=₹ 12,500(1+{12}/{100})^x

⇒ (1+{3}/{25})^x={15680}/{12500}={1568}/{1250}

⇒ ({28}/{25})^x={784}/{625}=({28}/{25})^2

⇒ ({28}/{25})^x=({28}/{25})^2

∴ x=2 \years

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