Sainik School Entrance Exam 2020 Solved Paper

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Question : 3 of 150

Marks: +1, -0

What is the value of

m

, if

({2}/{9})^3 ×({2}/{9})^{-6}=({2}/{9})^{2 m-1}

$m=1$
$m=-2$
$m=-1$
$m=2$

Solution:

(c) From the question,

({2}/{9})^3 ×({2}/{9})^{-6}=({2}/{9})^{2 m-1}

∴

(2/9)^{3-6}= (2/9)^{2m-1}

⇒

(2/9)^{-3}= (2/9)^{2m-1}

⇒

-3=2m-1

⇒

2m=-3+1=-2

⇒

m=-2/2=-1

∴ the value of

m=-1

.

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