Sainik School Entrance Exam 2020 Solved Paper

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Question : 27 of 150

Marks: +1, -0

∛{(-x^6×y^3×z^{21})/{z^9×x^{12}}

=_________

${-y z^3}/{x^2}$
${y z^4}/{x^2}$
${-x y^4}/{z^2}$
${-y z^4}/{x^2}$

Solution:

(d)

∛{(-x^6×y^3×z^{21})/{z^9×x^{12}}

=

({-x^6×y^3×z^{21}}/{z^9×x^{12}})^{1/3}

=({-x^6×y^3×z^{12}×z^9}/{z^9×x^6×x^6})^{1/3}

=({-y^3×z^{12}}/x^6)^{1/3}

=({(-y)^3×(z^4)^3}/x^6)^{1/3}

=

-{yz^4}/{x^2}

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