Sainik School Entrance Exam 2020 Solved Paper

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Question : 12 of 150

Marks: +1, -0

The value of

{4 m^2-a^2+2 a b-b^2}/{2 m+a-b}

is

$(2 m-a+b)$
$(2 m-a-b)$
$(2 m+a+b)$
$(2 m+a-b)$

Solution:

(a)

{4m^2-(a^2-2ab+b^2)}/{2m+a-b}

={4m^2-(a-b)^2}/{2m+a-b}

={(2m)^2-(a-b)^2}/{2m+a-b}

={(2m-a+b)(2m+a-b)}/{2m+a-b}

=2m-a+b

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