Sainik School Entrance Exam 2019 Solved Paper

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Question : 50 of 150

Marks: +1, -0

The value of

(10001)^2

1002001
100201
100020001
1000201

Solution:

(c)

(10001)^2

We can break

(10001)^2

this as

(10000+1)^2

=(10000)^2+(1)^2+2 ×(10000) ×(1)

=100000000+1+20000....[∵ (a+b)^2=a^2+b^2+2 a b]

=100020001

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