[(\frac{1}{2})^{-1}+(\frac{2}{3})^2-(\frac{3}{4})^0]^{-2} is equal to:

Sainik School Entrance Exam 2019 Solved Paper

Question : 5 of 150

Marks: +1, -0

[({1}/{2})^{-1}+({2}/{3})^2-({3}/{4})^0]^{-2}

is equal to:

Solution:

[({1}/{2})^{-1}+({2}/{3})^2-({3}/{4})^0]^{-2}

= [2+4/9-1]^{-2}

= [13/9]^{-2} = [9/13]^2 [∵(y/x)^{-1} = x/y]

= {9×9}/{13×13} = 81/169

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