Sainik School Entrance Exam 2019 Solved Paper

Question : 33 of 150

Marks: +1, -0

The smallest square number which is divisible by each one of the numbers

8,9,10

Solution:

(b) The smallest number which is divisible by 8,9 and 10

=\LCM (8,9,10)

=2×2×2×3×3×5=360

So, to make 360 perfect square
we have to multiply by

2×5

∴ Required smallest number

= 360×2×5

=3600

Go to Question:

Prev Question

Next Question