Sainik School Entrance Exam 2018 Solved Paper

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Question : 47 of 150

Marks: +1, -0

3+23 y-8 y^2

is equal to :

$(1-8y) (3+y)$
$(1+8y) (3-y)$
$(1-8y) (y-3)$
$(8y-1) (y+3)$

Solution:

(b)

-8 y^2+23 y+3

=-8 y^2+24 y-y+3

=-8 y(y-3)-1(y-3)

= (y-3)(-8 y-1)

=(1+8 y)(3-y)

.

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