Sainik School Entrance Exam 2018 Solved Paper

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Question : 35 of 150

Marks: +1, -0

{3^n.3^{2 n+1}}/{9^n.3^{n-1}}

is equal to

1
9
3
$3^n$

Solution:

(b)

{3^n.3^{2 n+1}}/{9^n.3^{n-1}}={3^{2 n+1+n}}/{(3^2)^n.3^{n-1}}

=

{3^{3 n+1}}/{3^{2 n+n-1}}= {3^{3 n+1}}/{3^{3 n-1}}

=

3^{3 n+1-3 n+1}

=

3^2=9

.

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