Sainik School Entrance Exam 2018 Solved Paper

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Question : 20 of 150

Marks: +1, -0

Given that

3048625=3375 ×729

. Then what is the cube root of

3048625 ?

155
135
45
None of these

Solution:

(b) ∴

3048625=3375 ×729

=5 ×5 ×5 × 3 ×3 ×3 ×9 ×9 ×9

∵

∛{3048625}

= ∛{5×5 ×5 ×3 ×3 ×3 ×9 ×9 ×9}

=5 ×3 ×9=135

So, cube root of

3048625=135

.

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