RRB RPF RPSF SI and CONS Model Papers 8 with solutions

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Question : 50 of 120

Marks: +1, -0

Find the length of the largest rod that can be placed in a room 16m long, 12m broad and

10 2 /3

m. high.

23 m.
68 m.
$22 2 /3$ m.
$22 1/ 3$ m.

Solution:

(3)

Length of the largest rod

=√{ {L}^{2}+ {B}^{2}+ {H}^{2}}

= √{16^{2}+12^{2}+ ( {32}/{3} )^{2}}

=√{256+144+ {1029}/{9}}

=√{400+ {1029}/{9}}

=√{ {3600+1029}/{9}}

=√ { {4629}/{9}}=22 {2}/{5}

metres

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