RRB RPF RPSF SI and CONS Model Papers 7 with solutions

(1) (A + B)’s 1 day’s work $=\frac{1}{18}$
(B + C)’s 1 day’s work $=\frac{1}{24}$
(A + C)’s 1 day’s work $=\frac{1}{36}$
Adding all three,
2 (A + B + C)’s 1 day’s work
$=\frac{1}{18}+\frac{1}{24}+\frac{1}{36}$
$=\frac{4+3+2}{72}=\frac{1}{8}$
∴ (A + B + C)’ 1 day’s work $=\frac{1}{16}$
∴ A, B and C together will complete the work in 16 days.