RRB RPF RPSF SI and CONS Model Papers 6 with solutions

(3) Let us suppose that weight of sugar on the packet is marked 1kg.
Its actual weight = 90% of 1000 g = 900 g
Let C.P. of 100 g be ₹ 100.
C.P. of the packet = ₹ 900
S.P. of packet $=\left(\frac{100-\mathit{L}\%}{100}\times \mathit{C}.\mathit{P}.\right)$
$=(\frac{100-8}{100}\times \mathit{C}.\mathit{P}.$ of 1 $\mathit{k}\mathit{g})$
$=\mathit{₹}\left(\frac{92}{100}\times 1000\right)$
= ₹ 920
∴ Gain = ₹ 920 – ₹ 900 = ₹ 20
Gain% $=\left(\frac{20}{900}\times 100\mathrm{}\right)\%$ $=\frac{20}{9}\%=2\frac{2}{9}\%$