RRB RPF RPSF SI and CONS Model Papers 5 with solutions

Question : 41 of 119

Marks: +1, -0

A man starts a journey from home. He goes 5 km to the north, then proceeds 10 km to the right. From there, he again turns right and goes 10 km. How far is he from home? All distances are measured aerially.

$√200$ km
$√150$ km
$√225$ km
$√125$ km

Validate

Solution:

(4)

triangle AOB, AO = 10 km, OB = 10 – 5 = 5 km.
Now, He is AB

=√{5^2+10^2}

=√125

km far from his house.

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