RRB RPF RPSF SI and CONS Model Papers 4 with solutions

(1) C.P. of first car = ₹ 75000 S.P. of car $=\mathit{₹}\left(\frac{100+15}{100}\times 75000\right)$$=\mathit{₹}\left(\frac{115}{100}\times 75000\right)$$=\mathit{₹}86250$
C.P. of second car = ₹ 75000
Gain = 18%
S.P. of second car $=\mathit{₹}\left(\frac{100+18}{100}\times 75000\right)$ $=\mathit{₹}\left(\frac{118}{100}\times 75000\right)$ = ₹ 88500
Total C.P. of both the cars = ₹ 75000 + ₹ 75000 = ₹ 1,50,000
Total S.P. of both the cars = `₹ 86250 + ₹ 88500 = ₹ 1,74,750
Profit = 174750 – 150000=₹ 24750
∴ Required profit% $=\left(\frac{24750}{150000}\times 100\right)=16.5\%$