RRB RPF RPSF SI and CONS Model Papers 3 with solutions

Question : 11 of 120

Marks: +1, -0

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m, then the altitude of the triangle is :

100 m
200 m
$100√ 2$ m
$10 √2$ m

Validate

Solution:

(b) Let the common base be

x

m.
Now, area of the triangle = area of the parallelogram

{ 1 }/ { 2 }× x ×

Altitude of the triangle

= x × 100

Altitude of the triangle = 200 m

Go to Question:

Prev Question

Next Question