RRB RPF RPSF SI and CONS Model Papers 3 with solutions

Question : 1 of 120

Marks: +1, -0

PART A : MATHEMATICS

A number being successively divided by 3, 5 and 8 leaves 1,2 and 4 as remainders respectively. What are the remainders if the order of divisors be reversed?

3, 3, 1
3, 1, 3
1, 3, 3
None of these

Validate

Solution:

(a) Complete remainder

= { d } _ { 1 } { d } _ { 2 } { r } _ { 3 } + { d } _ { 1 } { r } _ { 2 } + { r } _ { 1 }

= 3 × 5 ×4 + 3 × 2 + 1 = 67

Divided 67 by 8, 5 and 3, the remainders are 3, 3, 1.

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