RRB Paramedical Staff Nurse Model Paper 5

Question : 59 of 100

Marks: +1, -0

If the radius of a cylindrical well is doubled and its height is reduced 25% up to of its original height. What is the percentage change in the volume of well?

500%
100%
250%
200%

Validate

Solution:

V_{1}=π r^{2} h

{V}_{2}=π(2 {r})^{2} × 3( {h}{/}4)=3 {πr}^{2} {h}

\%

change

=[( {V}_{2}- {V}_{1}){/}{V} 1] × 100=[(3-1){/} 1] × 100=200 \%

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