RRB Paramedical Staff Nurse Model Paper 4

Question : 50 of 100

Marks: +1, -0

A tank is fitted with two taps. The first tap can fill the tank completely in 45 min and the second tap can empty the full tank in 1 h. If both the taps are opened alternately for 1 min, then in how many hours the empty tank will be filled completely?

2 h 55 min
3 h 40 min
4 h 48 min
5 h 53 min

Validate

Solution:

Given, part of tank filled by A = 45 min
And emptied by B= 1 h or 60 min
Then, part of the tank filled in first 2 min

=\;{1}/{45}-\;{1}/{60}

=\;{4-3}/{180}=\;{1}/{180}

since,

\;{1}/{180}

part is filled in 2 min.
Thus,

1-\;{1}/{45}=\;{44}/{45}

part is filled in

\;{2 × 180 × 44}/{45}=352 {min}

i.e., 5 h 52 min
Remaining part will be filled in 1 min.
Thus total time taken = 5 h 53 min

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