RRB Paramedical Staff Nurse Model Paper 2

(2 men + 1 woman) can complete a work in 14 days
So, (2 men + 1 woman)'s 1 day's work $=\frac{1}{14}$
Hence, 2 men +1 woman$=\frac{1}{14}$ ......(i)
Similarly, 2 men + 4 woman $=\frac{1}{8}$ ...(ii)
On subtracting Eq (i) from Eq. (ii), we get
2 men $+$ 4 woman $=\frac{1}{8}$
2 men $+$ 1 woman $=\frac{1}{14}$
$-$  $-$     $-$
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    3 women $=\frac{1}{8}-\frac{1}{14}$
⇒ 3 women $=\frac{7-4}{56}=\frac{3}{56}$
⇒ 3 women $=\frac{3}{56}$
⇒ 1 woman $=\frac{1}{56}$
So, 1 woman can complete the whole work in 56 days
From Eq. (i),
⇒ 2 men $=\frac{1}{14}-\frac{1}{56}$
$=\frac{4-1}{56}$
⇒ 2 men $=\frac{3}{56}$
⇒ 1 man $=\frac{3}{2\times 56}$
So, 1 man can complete the whole work in $\frac{2\times 56}{3}$ days.
On comparing 1 man and 1 woman work,
56 women $=\frac{56\times 2}{3}\mathit{m}\mathit{e}\mathit{n}$
⇒ 1 woman $=\frac{2}{3}$ men
Hence, amount received by 1 man per day $=\mathrm{Rs}600$
Thus, amount received by 1 woman per day $=600\times \frac{2}{3}$
$=\mathrm{Rs}400$