RRB Paramedical Staff Nurse Model Paper 10

Question : 53 of 100

Marks: +1, -0

The distance between the points (2,7) and (k,-5) is 13 . What is the value of k ?

Solution:

distance section formula is
distance

=√{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

13=√{(2-k)^{2}+(7-(-5))^{2}}

13=√{(2-k)^{2}+(7+5)^{2}}

169=(2-k)^{2}+144

25=(2-k)^{2}

2-k=± 5

2-k=5

2- {k}=-5

k=-3

k=7

required answer

= 7

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