RRB NTPC प्रारंभिक हल सहित प्रैक्टिस टेस्ट 4

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Question : 34 of 100

Marks: +1, -0

यदि

{x}+{10}/{14}=√{{169}/{81}}

तो

{x}=?

0.730
0.830
0.936
0.562

Solution:

{x}+{10}/{14}=√{{169}/{81}}

{x}+{10}/{14}=13/9

x={13}/{9}-{10}/{14}=46/63=0.73

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