RRB NTPC Prelims Model Paper 5 with solutions

(1) 16 hours = 12 oxen
⇒ 4 horses = 3 oxen
∴ 4 horses and 2 oxen
= 3 oxen + 2 oxen = 5 oxen
∴12 oxen eat 14.4 quintalsof oats in 30 days.
∴ 1 oxen eat$\frac{14.4}{12\times 30}$quintals
of oats in 1 days.
∴5 oxen eat$\frac{14.4\times 5\times 5}{12\times 30}$
quintals of oats in 5 days.
$=\frac{144\times 5\times 5}{10\times 12\times 6}$
= 1 quintal.