RRB NTPC Prelims Model Paper 2 with solutions

Question : 93 of 101

Marks: +1, -0

Two poles of height 7 m and 12 m stand on a plane ground. If the distance between their feet is 12 m, the distance between their top will be

Solution:

PQ = TS = 7 m and QS = PT = 12 m,SR = 12 m
Here RT = SR – TS = 12 – 7 = 5 m
Now from △ PRT

PR =√{PT^2 +RT^2} =√{12^2 +5^2}

=√{144+ 25 }=13m

Go to Question:

Prev Question

Next Question