RRB NTPC Mains or Stage 2 Model Paper 9 with solutions

Question : 17 of 120

Marks: +1, -0

If the coordinates of the points A, B, C be (4, 4), (3, – 2) and (3, – 16) respectively, then the area of the triangle ABC is:

Solution:

(d)

1/2[4 (2 16) 3 ( 16 4) 3 (4 2)]

1/2[56 – 60 + 18] = 7

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