RRB NTPC Mains or Stage 2 Model Paper 8 with solutions

(b) Let the divisor be x
According to the question
Quotient will be $=\frac{\mathit{x}}{25}$
Remainder =$\frac{\mathit{x}}{5}$
Given, quotient = 16
So,$\frac{\mathit{x}}{25}=16$
$\therefore \mathit{x}=25\times 16$  ....(i)
Dividend
= Divisor × Quotient + remainder
$=\mathit{x}\times \frac{\mathit{x}}{25}+\frac{\mathit{x}}{5}=\frac{\mathit{x}}{5}\left[\frac{\mathit{x}}{5}+1\right]$
$=\frac{16\times 25}{5}\left[\frac{25\times 16}{5}+1\right]$[Putting the value of x]
=$\frac{16\times 25\times 405}{25}=6480$
OR, Divisor = 25 × 16 = 400
Remainder =$\frac{400}{5}=80$
∴Dividend
$=400\times 16+80=6480$