RRB NTPC Mains or Stage 2 Model Paper 7 with solutions

(d) First number = 8 and the sum of the digits of the second number is 2 + 8 = 10.
Thus, the difference of the first number and the sum of the digits of second number is 10 - 8 = 2.
Similarly, the sum of the digits of third number is 2 + 7 = 9.
Hence, the sum of digits of fourth number should be 2 more than 9 i.e. 11 and 6 + 5 = 11 Hence, (d) 65 is the correct option.