RRB NTPC Mains or Stage 2 Model Paper 6 with solutions

Question : 25 of 119

Marks: +1, -0

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60º and the angle of elevation of the top of the second tower from the foot of the first tower is 30º. The distance between the two towers in m times the height of the shorter tower. What is m equal to?

$√2$
$√ 3$
$1/ 2$
$1 /3$

Validate

Solution:

(b) Let the height of shorter tower be h thendistance between two tower = hm.

In ΔABD, tan 30º =

h/{mh} ⇒1/√3=1/m

∴m = √3

Go to Question:

Prev Question

Next Question