RRB NTPC Mains or Stage 2 Model Paper 6 with solutions

(b) Given , ∠BAX = 70° and ∠BAQ = 40°

∠QAX = 70° – 40° = 30°
∴∠EAX = 90°
⇒ ∠EAB = 90° – 70° = 20°
Since, AQBE is a cyclic quadrilateral.
∴ ∠EAQ +∠EBQ = 180°
⇒ ∠EBQ = 180° – 60° = 120°
But ∠EBA = 90°
∴ ∠ABQ = 120° – 90° = 30°