RRB NTPC Mains or Stage 2 Model Paper 6 with solutions

(c) Circumference of the circle= π × diameter
$=\frac{22}{7}\times 56=176$ cm
∴Perimeter of the square= (272 – 176 =) 96 cm
∴Side of the square
=$\left[\frac{96}{4}\right]=24$ cm
∴ Area of the square
= (24 × 24=) 576 sq cm
∴Area of the circle = $\mathit{\pi }{\mathit{r}}^2$
$=\frac{22}{7}\times 28\times 28=2464$ sq cm.
∴ Required sum= (576 + 2464) sq cm = 3040 sq cm