RRB NTPC Mains or Stage 2 Model Paper 4 with solutions

Question : 29 of 120

Marks: +1, -0

The average of four consecutive odd numbers is 36.What is the smallest of these numbers ?

Solution:

(d)

x + x + 2 + x + 4 + x + 6 = 4 × 36

⇒ 4x + 12 = 144 ⇒ 4x = 144 – 12

⇒ 4x = 132 ⇒ 132/4= 33

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