RRB NTPC Mains or Stage 2 Model Paper 4 with solutions

Question : 24 of 120

Marks: +1, -0

A hollow cylindrical iron pipe of length 1.4 m has base radius 2.5 cm and thickness of the metal is 1 cm. What is the volume of the iron used in the pipe?

2640 cu cm
2604 cu cm
2460 cu cm
None of these

Validate

Solution:

(a) \ Volume of pipe, V =π

( r^2_1-r^2_2 )× h

= 22/7 [(3.5)^2 (2.5)^2 ] ×140

=22 /7(12.25 -6.25) ×140

= 22 × 6 × 20 = 2640

cu cm

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