RRB NTPC Mains or Stage 2 Model Paper 4 with solutions

Question : 12 of 120

Marks: +1, -0

In the given figure, the side of square ABCD is 7 cm. What is the area of the shaded portion, formed by the arcs BD of the circles with centre at C and A?

$7 cm^2$
$28 cm^2$
$14 cm^2$
$21 cm^2$

Validate

Solution:

The above figure is symmetrical about BDArea of shaded part
= 2 × Area of BEDB
= 2 × (Area of BCDEB – Area of ΔBCD)
=

2 [{πr^2}/4-1 /2 ×BC× CD]

=2× 28/2 = 28 cm^2

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