RRB NTPC Mains or Stage 2 Model Paper 3 with solutions

Question : 9 of 120

Marks: +1, -0

The side BC of △ ABC is produced to D. I f ,

Solution:

∠ACD = ∠ABC + ∠BAC

108° ={∠BAC}/2+ ∠ BAC

108° = 3/2 ∠ BAC

∠ BAC ={108 ×2}/3= 72°

Go to Question:

Prev Question

Next Question