RRB NTPC Mains or Stage 2 Model Paper 3 with solutions

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Question : 5 of 120

Marks: +1, -0

If

2 - cos^2

= 3 sin θcosθ, sin θ≠cosθ, then tan θis

$1 /2$
0
$2/ 3$
$1 /3$

Solution:

2 – cos^2 θ = 3 sin θ. cos θ

Divide by cos^2θ

2sec^2 θ – 1 = 3 tan θ

2(1 + tan^2 θ) – 1 = 3tan θ

2tan^2 θ – 3 tan θ + 1 = 0

tan θ

=1/2

or tan θ = 1

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