\sec^4 \theta-\sec^2 \theta is equal to

Correct Answer is : tan2°+tan4°

RRB NTPC Mains or Stage 2 Model Paper 3 with solutions

Question : 21 of 120

Marks: +1, -0

sec^4 θ-sec^2 θ

is equal to

Solution:

sec^4 θ – sec^2 θ = sec^2 θ (sec^2 θ – 1)

= (1 + tan^2 θ )(1 + tan^2 θ – 1)

= tan^2 θ + tan^4 θ

Go to Question:

Prev Question

Next Question