RRB NTPC Mains or Stage 2 Model Paper 3 with solutions

Question : 17 of 120

Marks: +1, -0

In xy-plane, P and Q are two points having co-ordinates (2, 0) and (5, 4) respectively. Then the numberical value of the area of the circle with radius PQ , is

16π
32π
14π
25π

Validate

Solution:

PQ = √{(5 -2)^2 +(4 -0)^2}

PQ =√ {9 +16 }= 5

Area of circle with radius

PQ = π(PQ)^2

= π(5)^2 = 25π

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