RRB NTPC Mains or Stage 2 Model Paper 2 with solutions

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Question : 94 of 120

Marks: +1, -0

If Sin

x = 4 /5

, then Sec x + Tan x = ?

1/3
31/12
37/20
3

Solution:

d)sin

4/5

,x = then, sec x + tan x = ?

∵sinθ= p/h=4/5

∴b =√{ h^2 - p^2} = √{(5)^2 - (4)^2} = √{25 -16} ⇒ √9 = 3

∴sec x +tan x

=h /b+p/ b

⇒5/3+ 4/3⇒ {5 +4} /3=9/3=3

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