RRB NTPC Mains or Stage 2 Model Paper 10 with solutions

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Question : 24 of 120

Marks: +1, -0

If

x^2 + 2 1 x = 38

then find the value of

x – 1/ x .

+ 6
– 6
± 6
± 9

Solution:

(c)

∵[x- 1 /x]^2= = x^2 +1/{x^ 2}-2× 1/ x × = 38 –

2 = 36

∵[x- 1/ x] ±√ 36 = ± 6

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