RRB NTPC Mains or Stage 2 Model Paper 10 with solutions

Question : 15 of 120

Marks: +1, -0

The perimeter of a square is one-fourth the perimeter of a rectangle. If the perimeter of the square is 44 cm and the length of the rectangle is 51 cm, what is the difference between the breadth of the rectangle and the side of the square?

30 cm
18 cm
26 cm
32 cm

Validate

Solution:

\text"circumference"/4

44 /4=11

cm
Circumference of rectangle = 4 × perimeter of square

= 4 × 44 = 176

cm
width of rectangle

= \text"circumference of rectangle"/\text"2" – length

=176/2- 51 =88- 51= 37 cm.

∴Required difference = width – side = 37 – 11= 26 cm.

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