If sec θ = 5x and tan θ = \frac{5}{x}, then the value of 10 (x^{2}−\frac{1}{x^{2}}) is:

RRB NTPC CBT I 4 Jan 2021 Shift 2 Paper

Question : 84 of 100

Marks: +1, -0

If sec θ = 5x and tan θ =

\;{5}/{x}

, then the value of

10 (x^{2}−\;{1}/{x^{2}})

is:

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