RRB NTPC CBT I 4 Jan 2021 Shift 2 Paper
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Question : 41 of 100
Marks:
+1,
-0
If x and y are two positive numbers such that
√x = 8 and x2 + y = 4112, then the find the value of √y.
√x = 8 and x2 + y = 4112, then the find the value of √y.
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