Find the rate of interest for a sum that becomes \frac{14641}{10000} times of itself in 4 years compounded annually.

RRB NTPC CBT I 4 Jan 2021 Shift 2 Paper

Question : 19 of 100

Marks: +1, -0

Find the rate of interest for a sum that becomes

\;{14641}/{10000}

times of itself in 4 years compounded annually.

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