{ \sin 27^{\circ} \cos 63^{\circ}}/{\cos ^2 27^{\circ}}- { \sec 27^{\circ} {\cosec} 63^{\circ}}/{\tan ^2 45^{\circ}} is:

RRB NTPC CBT I 29 Dec 2020 Shift 2 Paper

Question : 48 of 100

Marks: +1, -0

\;{ sin \;27^{∘} \cos 63^{∘}}/{\cos ^2 27^{∘}}-\;{\ sec 27^{∘} {\cosec} 63^{∘}}/{\tan ^2 45^{∘}}

is:

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